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1230333132407 is a prime number
BaseRepresentation
bin10001111001110101100…
…100011011111001110111
311100121201000211220002212
4101321311210123321313
5130124210240214112
62341112432524035
7154613542034261
oct21716544337167
94317630756085
101230333132407
11434865a84465
1217a5440b061b
138c0349ab572
1443796cccb31
152200cbba522
hex11e7591be77

1230333132407 has 2 divisors, whose sum is σ = 1230333132408. Its totient is φ = 1230333132406.

The previous prime is 1230333132307. The next prime is 1230333132409. The reversal of 1230333132407 is 7042313330321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1230333132407 - 210 = 1230333131383 is a prime.

It is a super-2 number, since 2×12303331324072 (a number of 25 digits) contains 22 as substring.

Together with 1230333132409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1230333132409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615166566203 + 615166566204.

It is an arithmetic number, because the mean of its divisors is an integer number (615166566204).

Almost surely, 21230333132407 is an apocalyptic number.

1230333132407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1230333132407 is an equidigital number, since it uses as much as digits as its factorization.

1230333132407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 32.

Adding to 1230333132407 its reverse (7042313330321), we get a palindrome (8272646462728).

The spelling of 1230333132407 in words is "one trillion, two hundred thirty billion, three hundred thirty-three million, one hundred thirty-two thousand, four hundred seven".