Base | Representation |
---|---|
bin | 10001111001110101100… |
… | …100011011111001110111 |
3 | 11100121201000211220002212 |
4 | 101321311210123321313 |
5 | 130124210240214112 |
6 | 2341112432524035 |
7 | 154613542034261 |
oct | 21716544337167 |
9 | 4317630756085 |
10 | 1230333132407 |
11 | 434865a84465 |
12 | 17a5440b061b |
13 | 8c0349ab572 |
14 | 43796cccb31 |
15 | 2200cbba522 |
hex | 11e7591be77 |
1230333132407 has 2 divisors, whose sum is σ = 1230333132408. Its totient is φ = 1230333132406.
The previous prime is 1230333132307. The next prime is 1230333132409. The reversal of 1230333132407 is 7042313330321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1230333132407 - 210 = 1230333131383 is a prime.
It is a super-2 number, since 2×12303331324072 (a number of 25 digits) contains 22 as substring.
Together with 1230333132409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1230333132409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615166566203 + 615166566204.
It is an arithmetic number, because the mean of its divisors is an integer number (615166566204).
Almost surely, 21230333132407 is an apocalyptic number.
1230333132407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230333132407 is an equidigital number, since it uses as much as digits as its factorization.
1230333132407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27216, while the sum is 32.
Adding to 1230333132407 its reverse (7042313330321), we get a palindrome (8272646462728).
The spelling of 1230333132407 in words is "one trillion, two hundred thirty billion, three hundred thirty-three million, one hundred thirty-two thousand, four hundred seven".
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