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12303350159 is a prime number
BaseRepresentation
bin10110111010101011…
…00011100110001111
31011202102220221112112
423131111203212033
5200144124201114
65352503254235
7613613515352
oct133525434617
934672827475
1012303350159
115243a14091
12247444a37b
131210c66469
1484a024299
154c01e213e
hex2dd56398f

12303350159 has 2 divisors, whose sum is σ = 12303350160. Its totient is φ = 12303350158.

The previous prime is 12303350089. The next prime is 12303350161. The reversal of 12303350159 is 95105330321.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12303350159 is a prime.

It is a super-4 number, since 4×123033501594 (a number of 41 digits) contains 4444 as substring.

Together with 12303350161, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12303350179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151675079 + 6151675080.

It is an arithmetic number, because the mean of its divisors is an integer number (6151675080).

Almost surely, 212303350159 is an apocalyptic number.

12303350159 is a deficient number, since it is larger than the sum of its proper divisors (1).

12303350159 is an equidigital number, since it uses as much as digits as its factorization.

12303350159 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12150, while the sum is 32.

The spelling of 12303350159 in words is "twelve billion, three hundred three million, three hundred fifty thousand, one hundred fifty-nine".