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123040413437 is a prime number
BaseRepresentation
bin111001010010111000…
…1111011011011111101
3102202120220020121122112
41302211301323123331
54003441321212222
6132305103023405
711614025154344
oct1624561733375
9382526217575
10123040413437
11481aa1187a7
121ba19b9ab65
13b7ab07b686
145d5306cb5b
153301d7dbe2
hex1ca5c7b6fd

123040413437 has 2 divisors, whose sum is σ = 123040413438. Its totient is φ = 123040413436.

The previous prime is 123040413403. The next prime is 123040413449. The reversal of 123040413437 is 734314040321.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89117772676 + 33922640761 = 298526^2 + 184181^2 .

It is an emirp because it is prime and its reverse (734314040321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123040413437 - 210 = 123040412413 is a prime.

It is a super-3 number, since 3×1230404134373 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123040413467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61520206718 + 61520206719.

It is an arithmetic number, because the mean of its divisors is an integer number (61520206719).

Almost surely, 2123040413437 is an apocalyptic number.

It is an amenable number.

123040413437 is a deficient number, since it is larger than the sum of its proper divisors (1).

123040413437 is an equidigital number, since it uses as much as digits as its factorization.

123040413437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 32.

Adding to 123040413437 its reverse (734314040321), we get a palindrome (857354453758).

The spelling of 123040413437 in words is "one hundred twenty-three billion, forty million, four hundred thirteen thousand, four hundred thirty-seven".