Base | Representation |
---|---|
bin | 11011111111100001000101… |
… | …101101000011011110000100 |
3 | 121010220101212202120120101110 |
4 | 123333201011231003132010 |
5 | 112114032101133324030 |
6 | 1113500531245525020 |
7 | 34634361621622500 |
oct | 3377410555033604 |
9 | 533811782516343 |
10 | 123112112011140 |
11 | 3625560a78224a |
12 | 11983b51273770 |
13 | 5390564b8b6b5 |
14 | 225892d841300 |
15 | e376665cd1b0 |
hex | 6ff845b43784 |
123112112011140 has 144 divisors (see below), whose sum is σ = 401111465916672. Its totient is φ = 28131649588224.
The previous prime is 123112112011121. The next prime is 123112112011153. The reversal of 123112112011140 is 41110211211321.
It is a super-3 number, since 3×1231121120111403 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3871164 + ... + 16161996.
It is an arithmetic number, because the mean of its divisors is an integer number (2785496291088).
Almost surely, 2123112112011140 is an apocalyptic number.
123112112011140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 123112112011140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (200555732958336).
123112112011140 is an abundant number, since it is smaller than the sum of its proper divisors (277999353905532).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123112112011140 is a wasteful number, since it uses less digits than its factorization.
123112112011140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12294266 (or 12294257 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 21.
Adding to 123112112011140 its reverse (41110211211321), we get a palindrome (164222323222461).
The spelling of 123112112011140 in words is "one hundred twenty-three trillion, one hundred twelve billion, one hundred twelve million, eleven thousand, one hundred forty".
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