Base | Representation |
---|---|
bin | 1011001101001011010110… |
… | …0101000101110011011111 |
3 | 1121121212200112221000111212 |
4 | 2303102311211011303133 |
5 | 3103331413211313002 |
6 | 42112110044135035 |
7 | 2411110115066363 |
oct | 263226545056337 |
9 | 47555615830455 |
10 | 12321012604127 |
11 | 3a20348452637 |
12 | 146ba8a23747b |
13 | 6b4b35927256 |
14 | 3084a96b52a3 |
15 | 1657701bb352 |
hex | b34b5945cdf |
12321012604127 has 2 divisors, whose sum is σ = 12321012604128. Its totient is φ = 12321012604126.
The previous prime is 12321012604009. The next prime is 12321012604157. The reversal of 12321012604127 is 72140621012321.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12321012604127 - 28 = 12321012603871 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12321012604093 and 12321012604102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12321012604157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160506302063 + 6160506302064.
It is an arithmetic number, because the mean of its divisors is an integer number (6160506302064).
Almost surely, 212321012604127 is an apocalyptic number.
12321012604127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12321012604127 is an equidigital number, since it uses as much as digits as its factorization.
12321012604127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 12321012604127 its reverse (72140621012321), we get a palindrome (84461633616448).
The spelling of 12321012604127 in words is "twelve trillion, three hundred twenty-one billion, twelve million, six hundred four thousand, one hundred twenty-seven".
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