Base | Representation |
---|---|
bin | 10110111100110100… |
… | …11101000100001111 |
3 | 1011210200220112211021 |
4 | 23132122131010033 |
5 | 200213240130333 |
6 | 5354350335011 |
7 | 614223161023 |
oct | 133632350417 |
9 | 34720815737 |
10 | 12321411343 |
11 | 525312a78a |
12 | 247a4ba467 |
13 | 121491b257 |
14 | 84c5a6383 |
15 | 4c1aad82d |
hex | 2de69d10f |
12321411343 has 2 divisors, whose sum is σ = 12321411344. Its totient is φ = 12321411342.
The previous prime is 12321411341. The next prime is 12321411367. The reversal of 12321411343 is 34311412321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12321411343 - 21 = 12321411341 is a prime.
Together with 12321411341, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12321411341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160705671 + 6160705672.
It is an arithmetic number, because the mean of its divisors is an integer number (6160705672).
Almost surely, 212321411343 is an apocalyptic number.
12321411343 is a deficient number, since it is larger than the sum of its proper divisors (1).
12321411343 is an equidigital number, since it uses as much as digits as its factorization.
12321411343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1728, while the sum is 25.
Adding to 12321411343 its reverse (34311412321), we get a palindrome (46632823664).
The spelling of 12321411343 in words is "twelve billion, three hundred twenty-one million, four hundred eleven thousand, three hundred forty-three".
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