Base | Representation |
---|---|
bin | 1011001101101101010001… |
… | …1100001101001011001111 |
3 | 1121122202012021200002000212 |
4 | 2303123110130031023033 |
5 | 3104004041244201221 |
6 | 42120213513513035 |
7 | 2411551606210256 |
oct | 263332434151317 |
9 | 47582167602025 |
10 | 12330120303311 |
11 | 3a241a1513858 |
12 | 14717b041277b |
13 | 6b59577b5575 |
14 | 308ad112379d |
15 | 165b04a6db5b |
hex | b36d470d2cf |
12330120303311 has 2 divisors, whose sum is σ = 12330120303312. Its totient is φ = 12330120303310.
The previous prime is 12330120303283. The next prime is 12330120303313. The reversal of 12330120303311 is 11330302103321.
It is a strong prime.
It is an emirp because it is prime and its reverse (11330302103321) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12330120303311 is a prime.
Together with 12330120303313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12330120303313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165060151655 + 6165060151656.
It is an arithmetic number, because the mean of its divisors is an integer number (6165060151656).
Almost surely, 212330120303311 is an apocalyptic number.
12330120303311 is a deficient number, since it is larger than the sum of its proper divisors (1).
12330120303311 is an equidigital number, since it uses as much as digits as its factorization.
12330120303311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 12330120303311 its reverse (11330302103321), we get a palindrome (23660422406632).
The spelling of 12330120303311 in words is "twelve trillion, three hundred thirty billion, one hundred twenty million, three hundred three thousand, three hundred eleven".
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