Base | Representation |
---|---|
bin | 11100000010011001011110… |
… | …110010010101011000000111 |
3 | 121011121022220222101121211221 |
4 | 130002121132302111120013 |
5 | 112130303041414234343 |
6 | 1114131513431541211 |
7 | 34654601156162665 |
oct | 3402313662253007 |
9 | 534538828347757 |
10 | 123310101321223 |
11 | 3632157a565343 |
12 | 119b63a752a807 |
13 | 53a612875c90b |
14 | 2264352883c35 |
15 | e3c8a327c5ed |
hex | 70265ec95607 |
123310101321223 has 2 divisors, whose sum is σ = 123310101321224. Its totient is φ = 123310101321222.
The previous prime is 123310101321221. The next prime is 123310101321373. The reversal of 123310101321223 is 322123101013321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123310101321223 - 21 = 123310101321221 is a prime.
Together with 123310101321221, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123310101321221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61655050660611 + 61655050660612.
It is an arithmetic number, because the mean of its divisors is an integer number (61655050660612).
Almost surely, 2123310101321223 is an apocalyptic number.
123310101321223 is a deficient number, since it is larger than the sum of its proper divisors (1).
123310101321223 is an equidigital number, since it uses as much as digits as its factorization.
123310101321223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 123310101321223 its reverse (322123101013321), we get a palindrome (445433202334544).
The spelling of 123310101321223 in words is "one hundred twenty-three trillion, three hundred ten billion, one hundred one million, three hundred twenty-one thousand, two hundred twenty-three".
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