Base | Representation |
---|---|
bin | 111001011101101110… |
… | …1110100110011100111 |
3 | 102210112020212000211002 |
4 | 1302323131310303213 |
5 | 4010212441222101 |
6 | 132405141103515 |
7 | 11626033515431 |
oct | 1627335646347 |
9 | 383466760732 |
10 | 123404242151 |
11 | 48376528693 |
12 | 1babb9b7b9b |
13 | b838567038 |
14 | 5d894d9651 |
15 | 3323c99d6b |
hex | 1cbb774ce7 |
123404242151 has 2 divisors, whose sum is σ = 123404242152. Its totient is φ = 123404242150.
The previous prime is 123404242061. The next prime is 123404242153. The reversal of 123404242151 is 151242404321.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (151242404321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123404242151 - 222 = 123400047847 is a prime.
Together with 123404242153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123404242153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61702121075 + 61702121076.
It is an arithmetic number, because the mean of its divisors is an integer number (61702121076).
Almost surely, 2123404242151 is an apocalyptic number.
123404242151 is a deficient number, since it is larger than the sum of its proper divisors (1).
123404242151 is an equidigital number, since it uses as much as digits as its factorization.
123404242151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 123404242151 its reverse (151242404321), we get a palindrome (274646646472).
The spelling of 123404242151 in words is "one hundred twenty-three billion, four hundred four million, two hundred forty-two thousand, one hundred fifty-one".
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