123471300500 has 48 divisors (see below), whose sum is σ = 283854043200. Its totient is φ = 46789120800.

The previous prime is 123471300467. The next prime is 123471300517. The reversal of 123471300500 is 5003174321.

It is a super-2 number, since 2×123471300500² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 123471300500.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6488990 + ... + 6507989.

It is an arithmetic number, because the mean of its divisors is an integer number (5913625900).

Almost surely, 2^123471300500 is an apocalyptic number.

123471300500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

123471300500 is an abundant number, since it is smaller than the sum of its proper divisors (160382742700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123471300500 is a wasteful number, since it uses less digits than its factorization.

123471300500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12997017 (or 12997005 counting only the distinct ones).

The product of its (nonzero) digits is 2520, while the sum is 26.

Adding to 123471300500 its reverse (5003174321), we get a palindrome (128474474821).

The spelling of 123471300500 in words is "one hundred twenty-three billion, four hundred seventy-one million, three hundred thousand, five hundred".