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1240343331431 is a prime number
BaseRepresentation
bin10010000011001010001…
…110010100001001100111
311101120112122210200122212
4102003022032110021213
5130310210343101211
62345450022114035
7155416602235061
oct22031216241147
94346478720585
101240343331431
11439032525116
1218047857b91b
138cc6b82a059
1444066548731
15223e68e038b
hex120ca394267

1240343331431 has 2 divisors, whose sum is σ = 1240343331432. Its totient is φ = 1240343331430.

The previous prime is 1240343331287. The next prime is 1240343331439. The reversal of 1240343331431 is 1341333430421.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1341333430421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1240343331431 - 222 = 1240339137127 is a prime.

It is a super-2 number, since 2×12403433314312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240343331439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620171665715 + 620171665716.

It is an arithmetic number, because the mean of its divisors is an integer number (620171665716).

Almost surely, 21240343331431 is an apocalyptic number.

1240343331431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240343331431 is an equidigital number, since it uses as much as digits as its factorization.

1240343331431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 32.

Adding to 1240343331431 its reverse (1341333430421), we get a palindrome (2581676761852).

The spelling of 1240343331431 in words is "one trillion, two hundred forty billion, three hundred forty-three million, three hundred thirty-one thousand, four hundred thirty-one".