12405312214301 has 2 divisors, whose sum is σ = 12405312214302. Its totient is φ = 12405312214300.

The previous prime is 12405312214289. The next prime is 12405312214303. The reversal of 12405312214301 is 10341221350421.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8349817056025 + 4055495158276 = 2889605^2 + 2013826^2 .

It is a cyclic number.

It is not a de Polignac number, because 12405312214301 - 2¹⁴ = 12405312197917 is a prime.

It is a super-2 number, since 2×12405312214301² (a number of 27 digits) contains 22 as substring.

Together with 12405312214303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12405312214303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6202656107150 + 6202656107151.

It is an arithmetic number, because the mean of its divisors is an integer number (6202656107151).

Almost surely, 2^{12405312214301} is an apocalyptic number.

It is an amenable number.

12405312214301 is a deficient number, since it is larger than the sum of its proper divisors (1).

12405312214301 is an equidigital number, since it uses as much as digits as its factorization.

12405312214301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 12405312214301 its reverse (10341221350421), we get a palindrome (22746533564722).

The spelling of 12405312214301 in words is "twelve trillion, four hundred five billion, three hundred twelve million, two hundred fourteen thousand, three hundred one".