Base | Representation |
---|---|
bin | 101111011000… |
… | …010000110110 |
3 | 212101000020120 |
4 | 233120100312 |
5 | 11134421100 |
6 | 1122112410 |
7 | 210366231 |
oct | 57302066 |
9 | 25330216 |
10 | 12420150 |
11 | 7013496 |
12 | 41ab706 |
13 | 275b302 |
14 | 1914418 |
15 | 11550a0 |
hex | bd8436 |
12420150 has 48 divisors (see below), whose sum is σ = 31807488. Its totient is φ = 3204000.
The previous prime is 12420139. The next prime is 12420151. The reversal of 12420150 is 5102421.
12420150 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12420151) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3315 + ... + 5985.
It is an arithmetic number, because the mean of its divisors is an integer number (662656).
Almost surely, 212420150 is an apocalyptic number.
12420150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 12420150, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15903744).
12420150 is an abundant number, since it is smaller than the sum of its proper divisors (19387338).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12420150 is a wasteful number, since it uses less digits than its factorization.
12420150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2717 (or 2712 counting only the distinct ones).
The product of its (nonzero) digits is 80, while the sum is 15.
The square root of 12420150 is about 3524.2233186902. The cubic root of 12420150 is about 231.5842111769.
Adding to 12420150 its reverse (5102421), we get a palindrome (17522571).
It can be divided in two parts, 124201 and 50, that added together give a triangular number (124251 = T498).
The spelling of 12420150 in words is "twelve million, four hundred twenty thousand, one hundred fifty".
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