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12423223450343 is a prime number
BaseRepresentation
bin1011010011001000000111…
…0100100001101011100111
31121222122111210122222121202
42310302001310201223213
53112020230200402333
642231052225233115
72421356025666566
oct264620164415347
947878453588552
1012423223450343
113a5a728846172
12148785449279b
136c1674495104
1430d4041d7bdd
151682535665e8
hexb4c81d21ae7

12423223450343 has 2 divisors, whose sum is σ = 12423223450344. Its totient is φ = 12423223450342.

The previous prime is 12423223450307. The next prime is 12423223450381. The reversal of 12423223450343 is 34305432232421.

It is an a-pointer prime, because the next prime (12423223450381) can be obtained adding 12423223450343 to its sum of digits (38).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12423223450343 - 230 = 12422149708519 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12423223450297 and 12423223450306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12423223455343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6211611725171 + 6211611725172.

It is an arithmetic number, because the mean of its divisors is an integer number (6211611725172).

Almost surely, 212423223450343 is an apocalyptic number.

12423223450343 is a deficient number, since it is larger than the sum of its proper divisors (1).

12423223450343 is an equidigital number, since it uses as much as digits as its factorization.

12423223450343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 414720, while the sum is 38.

Adding to 12423223450343 its reverse (34305432232421), we get a palindrome (46728655682764).

The spelling of 12423223450343 in words is "twelve trillion, four hundred twenty-three billion, two hundred twenty-three million, four hundred fifty thousand, three hundred forty-three".