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1243002141421 is a prime number
BaseRepresentation
bin10010000101101000101…
…100110111101011101101
311101211101221211020021221
4102011220230313223231
5130331132022011141
62351005521423341
7155542515605515
oct22055054675355
94354357736257
101243002141421
1143a177338447
12180a9aa9ab51
13902a36213c1
14442396d8845
152250003abd1
hex12168b37aed

1243002141421 has 2 divisors, whose sum is σ = 1243002141422. Its totient is φ = 1243002141420.

The previous prime is 1243002141419. The next prime is 1243002141473. The reversal of 1243002141421 is 1241412003421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 805122165796 + 437879975625 = 897286^2 + 661725^2 .

It is an emirp because it is prime and its reverse (1241412003421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1243002141421 - 21 = 1243002141419 is a prime.

Together with 1243002141419, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1243002171421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621501070710 + 621501070711.

It is an arithmetic number, because the mean of its divisors is an integer number (621501070711).

Almost surely, 21243002141421 is an apocalyptic number.

It is an amenable number.

1243002141421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243002141421 is an equidigital number, since it uses as much as digits as its factorization.

1243002141421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1243002141421 its reverse (1241412003421), we get a palindrome (2484414144842).

The spelling of 1243002141421 in words is "one trillion, two hundred forty-three billion, two million, one hundred forty-one thousand, four hundred twenty-one".