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1243312207 is a prime number
BaseRepresentation
bin100101000011011…
…0111000001001111
310012122111210201021
41022012313001033
510021241442312
6323212255011
742544656634
oct11206670117
93178453637
101243312207
115888a9955
122a8471467
1316a77a7c7
14bb1a618b
1574243c07
hex4a1b704f

1243312207 has 2 divisors, whose sum is σ = 1243312208. Its totient is φ = 1243312206.

The previous prime is 1243312201. The next prime is 1243312229. The reversal of 1243312207 is 7022133421.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1243312207 - 23 = 1243312199 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1243312201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621656103 + 621656104.

It is an arithmetic number, because the mean of its divisors is an integer number (621656104).

Almost surely, 21243312207 is an apocalyptic number.

1243312207 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243312207 is an equidigital number, since it uses as much as digits as its factorization.

1243312207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 25.

The square root of 1243312207 is about 35260.6325382855. The cubic root of 1243312207 is about 1075.2927868800.

Adding to 1243312207 its reverse (7022133421), we get a palindrome (8265445628).

The spelling of 1243312207 in words is "one billion, two hundred forty-three million, three hundred twelve thousand, two hundred seven".