Base | Representation |
---|---|
bin | 100101000011011… |
… | …1000111101110100 |
3 | 10012122112012122120 |
4 | 1022012320331310 |
5 | 10021242221210 |
6 | 323212355540 |
7 | 42545022114 |
oct | 11206707564 |
9 | 3178465576 |
10 | 1243320180 |
11 | 588904943 |
12 | 2a8475bb0 |
13 | 16a78131b |
14 | bb1a9044 |
15 | 74246270 |
hex | 4a1b8f74 |
1243320180 has 48 divisors (see below), whose sum is σ = 3482828160. Its totient is φ = 331406208.
The previous prime is 1243320179. The next prime is 1243320181. The reversal of 1243320180 is 810233421.
1243320180 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (1243320179) and next prime (1243320181).
It is a self number, because there is not a number n which added to its sum of digits gives 1243320180.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1243320181) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 257226 + ... + 262014.
It is an arithmetic number, because the mean of its divisors is an integer number (72558920).
Almost surely, 21243320180 is an apocalyptic number.
1243320180 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1243320180 is an abundant number, since it is smaller than the sum of its proper divisors (2239507980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1243320180 is a wasteful number, since it uses less digits than its factorization.
1243320180 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9128 (or 9126 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
The square root of 1243320180 is about 35260.7455962009. The cubic root of 1243320180 is about 1075.2950853885.
The spelling of 1243320180 in words is "one billion, two hundred forty-three million, three hundred twenty thousand, one hundred eighty".
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