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12443311100 = 225211471012383
BaseRepresentation
bin10111001011010110…
…11101101111111100
31012010012021200212002
423211223131233330
5200440441423400
65414423201432
7620233253633
oct134553355774
935105250762
1012443311100
115305a19890
1224b32a6278
131233c5ba9c
1486085851a
154cc63bed5
hex2e5addbfc

12443311100 has 144 divisors (see below), whose sum is σ = 30394054656. Its totient is φ = 4382880000.

The previous prime is 12443311081. The next prime is 12443311103. The reversal of 12443311100 is 111334421.

It is a super-2 number, since 2×124433111002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12443311103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5220509 + ... + 5222891.

It is an arithmetic number, because the mean of its divisors is an integer number (211069824).

Almost surely, 212443311100 is an apocalyptic number.

12443311100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12443311100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15197027328).

12443311100 is an abundant number, since it is smaller than the sum of its proper divisors (17950743556).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12443311100 is a wasteful number, since it uses less digits than its factorization.

12443311100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2556 (or 2549 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 12443311100 its reverse (111334421), we get a palindrome (12554645521).

The spelling of 12443311100 in words is "twelve billion, four hundred forty-three million, three hundred eleven thousand, one hundred".

Divisors: 1 2 4 5 10 11 20 22 25 44 47 50 55 94 100 101 110 188 202 220 235 275 404 470 505 517 550 940 1010 1034 1100 1111 1175 2020 2068 2222 2350 2383 2525 2585 4444 4700 4747 4766 5050 5170 5555 9494 9532 10100 10340 11110 11915 12925 18988 22220 23735 23830 25850 26213 27775 47470 47660 51700 52217 52426 55550 59575 94940 104434 104852 111100 112001 118675 119150 131065 208868 224002 237350 238300 240683 261085 262130 448004 474700 481366 522170 524260 560005 655325 962732 1044340 1120010 1203415 1232011 1305425 1310650 2240020 2406830 2464022 2610850 2621300 2647513 2800025 4813660 4928044 5221700 5295026 5600050 6017075 6160055 10590052 11200100 11312101 12034150 12320110 13237565 22624202 24068300 24640220 26475130 30800275 45248404 52950260 56560505 61600550 66187825 113121010 123201100 124433111 132375650 226242020 248866222 264751300 282802525 497732444 565605050 622165555 1131210100 1244331110 2488662220 3110827775 6221655550 12443311100