12462443141 has 2 divisors, whose sum is σ = 12462443142. Its totient is φ = 12462443140.

The previous prime is 12462443131. The next prime is 12462443143. The reversal of 12462443141 is 14134426421.

12462443141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9207170116 + 3255273025 = 95954^2 + 57055^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12462443141 is a prime.

Together with 12462443143, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12462443098 and 12462443107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12462443143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6231221570 + 6231221571.

It is an arithmetic number, because the mean of its divisors is an integer number (6231221571).

Almost surely, 2^12462443141 is an apocalyptic number.

It is an amenable number.

12462443141 is a deficient number, since it is larger than the sum of its proper divisors (1).

12462443141 is an equidigital number, since it uses as much as digits as its factorization.

12462443141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18432, while the sum is 32.

Adding to 12462443141 its reverse (14134426421), we get a palindrome (26596869562).

The spelling of 12462443141 in words is "twelve billion, four hundred sixty-two million, four hundred forty-three thousand, one hundred forty-one".