Base | Representation |
---|---|
bin | 1011011000010010111000… |
… | …1011100010100111010110 |
3 | 1122022010200210201012010012 |
4 | 2312010232023202213112 |
5 | 3114444101203314200 |
6 | 42335535022000222 |
7 | 2430651245362412 |
oct | 266045613424726 |
9 | 48263623635105 |
10 | 12512014510550 |
11 | 3a94352004965 |
12 | 14a0ab4416072 |
13 | 6c9b549b2aa9 |
14 | 313828719d42 |
15 | 16a6ed6dda35 |
hex | b612e2e29d6 |
12512014510550 has 48 divisors (see below), whose sum is σ = 23588415430800. Its totient is φ = 4937235120000.
The previous prime is 12512014510403. The next prime is 12512014510573. The reversal of 12512014510550 is 5501541021521.
12512014510550 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×125120145105502 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3764576 + ... + 6260675.
It is an arithmetic number, because the mean of its divisors is an integer number (491425321475).
Almost surely, 212512014510550 is an apocalyptic number.
12512014510550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12512014510550 is a deficient number, since it is larger than the sum of its proper divisors (11076400920250).
12512014510550 is a wasteful number, since it uses less digits than its factorization.
12512014510550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10025601 (or 10025596 counting only the distinct ones).
The product of its (nonzero) digits is 10000, while the sum is 32.
The spelling of 12512014510550 in words is "twelve trillion, five hundred twelve billion, fourteen million, five hundred ten thousand, five hundred fifty".
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