Base | Representation |
---|---|
bin | 10010010000111111101… |
… | …101011011110111010010 |
3 | 11102222212222222101112222 |
4 | 102100333231123313102 |
5 | 131031122011410100 |
6 | 2400344113421042 |
7 | 156454003141424 |
oct | 22207755336722 |
9 | 4388788871488 |
10 | 1255199325650 |
11 | 444366329496 |
12 | 18332386a782 |
13 | 9149859568a |
14 | 44a755a4814 |
15 | 229b5c5b485 |
hex | 1243fb5bdd2 |
1255199325650 has 48 divisors (see below), whose sum is σ = 2472527462400. Its totient is φ = 472445625600.
The previous prime is 1255199325649. The next prime is 1255199325673. The reversal of 1255199325650 is 565239915521.
It is a super-2 number, since 2×12551993256502 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1255199325592 and 1255199325601.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3925295 + ... + 4233005.
It is an arithmetic number, because the mean of its divisors is an integer number (51510988800).
Almost surely, 21255199325650 is an apocalyptic number.
1255199325650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1255199325650 is a deficient number, since it is larger than the sum of its proper divisors (1217328136750).
1255199325650 is a wasteful number, since it uses less digits than its factorization.
1255199325650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 312539 (or 312534 counting only the distinct ones).
The product of its (nonzero) digits is 3645000, while the sum is 53.
The spelling of 1255199325650 in words is "one trillion, two hundred fifty-five billion, one hundred ninety-nine million, three hundred twenty-five thousand, six hundred fifty".
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