Base | Representation |
---|---|
bin | 10010010001010010111… |
… | …001000001110111111001 |
3 | 11110000201102111211220121 |
4 | 102101102321001313321 |
5 | 131032301402211100 |
6 | 2400440051053241 |
7 | 156464661352426 |
oct | 22212271016771 |
9 | 4400642454817 |
10 | 1255521132025 |
11 | 444510a47376 |
12 | 1833b35a1221 |
13 | 9151a159b54 |
14 | 44aa6212d4d |
15 | 229d412651a |
hex | 12452e41df9 |
1255521132025 has 48 divisors (see below), whose sum is σ = 1618107434496. Its totient is φ = 965798277120.
The previous prime is 1255521132017. The next prime is 1255521132059. The reversal of 1255521132025 is 5202311255521.
It is not a de Polignac number, because 1255521132025 - 23 = 1255521132017 is a prime.
It is a super-2 number, since 2×12555211320252 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15574372 + ... + 15654778.
It is an arithmetic number, because the mean of its divisors is an integer number (33710571552).
Almost surely, 21255521132025 is an apocalyptic number.
It is an amenable number.
1255521132025 is a deficient number, since it is larger than the sum of its proper divisors (362586302471).
1255521132025 is a wasteful number, since it uses less digits than its factorization.
1255521132025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80698 (or 80693 counting only the distinct ones).
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 1255521132025 its reverse (5202311255521), we get a palindrome (6457832387546).
The spelling of 1255521132025 in words is "one trillion, two hundred fifty-five billion, five hundred twenty-one million, one hundred thirty-two thousand, twenty-five".
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