Base | Representation |
---|---|
bin | 10111011111100110… |
… | …10010010010000000 |
3 | 1012120000211120022101 |
4 | 23233303102102000 |
5 | 201312430232230 |
6 | 5443331120144 |
7 | 624364602535 |
oct | 135763222200 |
9 | 35500746271 |
10 | 12613133440 |
11 | 539286a926 |
12 | 2540143054 |
13 | 12601ab28b |
14 | 879222d8c |
15 | 4dc4d4aca |
hex | 2efcd2480 |
12613133440 has 32 divisors (see below), whose sum is σ = 30153273660. Its totient is φ = 5045253120.
The previous prime is 12613133431. The next prime is 12613133453. The reversal of 12613133440 is 4433131621.
It can be written as a sum of positive squares in 2 ways, for example, as 10556329536 + 2056803904 = 102744^2 + 45352^2 .
It is a tau number, because it is divible by the number of its divisors (32).
It is a super-2 number, since 2×126131334402 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12613133399 and 12613133408.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9853371 + ... + 9854650.
Almost surely, 212613133440 is an apocalyptic number.
12613133440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12613133440 is an abundant number, since it is smaller than the sum of its proper divisors (17540140220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12613133440 is an equidigital number, since it uses as much as digits as its factorization.
12613133440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19708040 (or 19708028 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
The spelling of 12613133440 in words is "twelve billion, six hundred thirteen million, one hundred thirty-three thousand, four hundred forty".
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