Base | Representation |
---|---|
bin | 11100101100000010101101… |
… | …001100000011110001100010 |
3 | 121112201220122012110110020001 |
4 | 130230002231030003301202 |
5 | 113014144434404004400 |
6 | 1124202315441210214 |
7 | 35401421301252610 |
oct | 3454025514036142 |
9 | 545656565413201 |
10 | 126171864906850 |
11 | 3722520749a964 |
12 | 12198b5233096a |
13 | 5552c56bab109 |
14 | 2322a724666b0 |
15 | e8c046a13a6a |
hex | 72c0ad303c62 |
126171864906850 has 24 divisors (see below), whose sum is σ = 268205335688448. Its totient is φ = 43258925110800.
The previous prime is 126171864906827. The next prime is 126171864906851. The reversal of 126171864906850 is 58609468171621.
It is not an unprimeable number, because it can be changed into a prime (126171864906851) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 180245520946 + ... + 180245521645.
It is an arithmetic number, because the mean of its divisors is an integer number (11175222320352).
Almost surely, 2126171864906850 is an apocalyptic number.
126171864906850 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
126171864906850 is an abundant number, since it is smaller than the sum of its proper divisors (142033470781598).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
126171864906850 is a wasteful number, since it uses less digits than its factorization.
126171864906850 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 360491042610 (or 360491042605 counting only the distinct ones).
The product of its (nonzero) digits is 34836480, while the sum is 64.
The spelling of 126171864906850 in words is "one hundred twenty-six trillion, one hundred seventy-one billion, eight hundred sixty-four million, nine hundred six thousand, eight hundred fifty".
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