Base | Representation |
---|---|
bin | 11101001011010011100111… |
… | …111111001000011111110110 |
3 | 121211100022012210000121200102 |
4 | 131023103213333020133312 |
5 | 113304400021231201240 |
6 | 1132525314220114102 |
7 | 36012560345025512 |
oct | 3513234777103766 |
9 | 554308183017612 |
10 | 128320335022070 |
11 | 379833918a7804 |
12 | 12485410695932 |
13 | 567a72ba67c69 |
14 | 2398a47425142 |
15 | ec7d8e121815 |
hex | 74b4e7fc87f6 |
128320335022070 has 64 divisors (see below), whose sum is σ = 232831341160704. Its totient is φ = 50917392599040.
The previous prime is 128320335022031. The next prime is 128320335022081. The reversal of 128320335022070 is 70220533023821.
It is a super-2 number, since 2×1283203350220702 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1919406764 + ... + 1919473616.
It is an arithmetic number, because the mean of its divisors is an integer number (3637989705636).
Almost surely, 2128320335022070 is an apocalyptic number.
128320335022070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
128320335022070 is a deficient number, since it is larger than the sum of its proper divisors (104511006138634).
128320335022070 is a wasteful number, since it uses less digits than its factorization.
128320335022070 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69497.
The product of its (nonzero) digits is 120960, while the sum is 38.
Adding to 128320335022070 its reverse (70220533023821), we get a palindrome (198540868045891).
The spelling of 128320335022070 in words is "one hundred twenty-eight trillion, three hundred twenty billion, three hundred thirty-five million, twenty-two thousand, seventy".
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