Base | Representation |
---|---|
bin | 11101001111110111001101… |
… | …101000010101010001010110 |
3 | 121212110020100120220021210012 |
4 | 131033313031220111101112 |
5 | 113330012223403400240 |
6 | 1133325214014400222 |
7 | 36044313124533242 |
oct | 3517671550252126 |
9 | 555406316807705 |
10 | 128633425450070 |
11 | 37a94147222342 |
12 | 12516029b00072 |
13 | 56a110690a248 |
14 | 23a9c68d11422 |
15 | ed10b5b45b65 |
hex | 74fdcda15456 |
128633425450070 has 32 divisors (see below), whose sum is σ = 231825892320000. Its totient is φ = 51389878847616.
The previous prime is 128633425450067. The next prime is 128633425450139. The reversal of 128633425450070 is 70054524336821.
128633425450070 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 329324027 + ... + 329714393.
It is an arithmetic number, because the mean of its divisors is an integer number (7244559135000).
Almost surely, 2128633425450070 is an apocalyptic number.
128633425450070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
128633425450070 is a deficient number, since it is larger than the sum of its proper divisors (103192466869930).
128633425450070 is a wasteful number, since it uses less digits than its factorization.
128633425450070 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 430952.
The product of its (nonzero) digits is 4838400, while the sum is 50.
Adding to 128633425450070 its reverse (70054524336821), we get a palindrome (198687949786891).
The spelling of 128633425450070 in words is "one hundred twenty-eight trillion, six hundred thirty-three billion, four hundred twenty-five million, four hundred fifty thousand, seventy".
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