Base | Representation |
---|---|
bin | 11101010001110101000100… |
… | …100001111111010111110110 |
3 | 121212221011011122102020200020 |
4 | 131101311010201333113312 |
5 | 113334221004422344030 |
6 | 1133511243424230010 |
7 | 36060136030510563 |
oct | 3521650441772766 |
9 | 555834148366606 |
10 | 128768564262390 |
11 | 3803649459a1a8 |
12 | 1253826376b306 |
13 | 56b0a92323210 |
14 | 23b2608a9386a |
15 | ed4874bd0510 |
hex | 751d4487f5f6 |
128768564262390 has 32 divisors (see below), whose sum is σ = 332817212248416. Its totient is φ = 31696877356800.
The previous prime is 128768564262379. The next prime is 128768564262433. The reversal of 128768564262390 is 93262465867821.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 165087902511 + ... + 165087903290.
It is an arithmetic number, because the mean of its divisors is an integer number (10400537882763).
It is a 1-persistent number, because it is pandigital, but 2⋅128768564262390 = 257537128524780 is not.
Almost surely, 2128768564262390 is an apocalyptic number.
128768564262390 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
128768564262390 is an abundant number, since it is smaller than the sum of its proper divisors (204048647986026).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
128768564262390 is a wasteful number, since it uses less digits than its factorization.
128768564262390 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 330175805824.
The product of its (nonzero) digits is 418037760, while the sum is 69.
The spelling of 128768564262390 in words is "one hundred twenty-eight trillion, seven hundred sixty-eight billion, five hundred sixty-four million, two hundred sixty-two thousand, three hundred ninety".
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