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1297348518311 is a prime number
BaseRepresentation
bin10010111000001111111…
…111110110000110100111
311121000200110010020010122
4102320033333312012213
5132223432210041221
62431554345112155
7162505335312146
oct22701777660647
94530613106118
101297348518311
1146022546480a
1218b52748865b
139545499a871
1446b1338575d
1523b31275eab
hex12e0fff61a7

1297348518311 has 2 divisors, whose sum is σ = 1297348518312. Its totient is φ = 1297348518310.

The previous prime is 1297348518281. The next prime is 1297348518313. The reversal of 1297348518311 is 1138158437921.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1297348518311 - 26 = 1297348518247 is a prime.

It is a super-2 number, since 2×12973485183112 (a number of 25 digits) contains 22 as substring.

Together with 1297348518313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1297348518313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 648674259155 + 648674259156.

It is an arithmetic number, because the mean of its divisors is an integer number (648674259156).

Almost surely, 21297348518311 is an apocalyptic number.

1297348518311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1297348518311 is an equidigital number, since it uses as much as digits as its factorization.

1297348518311 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1451520, while the sum is 53.

The spelling of 1297348518311 in words is "one trillion, two hundred ninety-seven billion, three hundred forty-eight million, five hundred eighteen thousand, three hundred eleven".