Base | Representation |
---|---|
bin | 11000001011111011… |
… | …00001000110101111 |
3 | 1020111221101222211202 |
4 | 30011331201012233 |
5 | 203043114224401 |
6 | 5544251440115 |
7 | 636530644103 |
oct | 140575410657 |
9 | 36457358752 |
10 | 12984914351 |
11 | 5563711382 |
12 | 262475603b |
13 | 12bc21c396 |
14 | 8b275d903 |
15 | 50ee7206b |
hex | 305f611af |
12984914351 has 2 divisors, whose sum is σ = 12984914352. Its totient is φ = 12984914350.
The previous prime is 12984914321. The next prime is 12984914353. The reversal of 12984914351 is 15341948921.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12984914351 - 222 = 12980720047 is a prime.
Together with 12984914353, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 12984914296 and 12984914305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12984914353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6492457175 + 6492457176.
It is an arithmetic number, because the mean of its divisors is an integer number (6492457176).
Almost surely, 212984914351 is an apocalyptic number.
12984914351 is a deficient number, since it is larger than the sum of its proper divisors (1).
12984914351 is an equidigital number, since it uses as much as digits as its factorization.
12984914351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 311040, while the sum is 47.
The spelling of 12984914351 in words is "twelve billion, nine hundred eighty-four million, nine hundred fourteen thousand, three hundred fifty-one".
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