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13000000000032 = 253215121979689
BaseRepresentation
bin1011110100101100110001…
…1000011101000000100000
31201000210021100111112022200
42331023030120131000200
53200443000000000112
643352041220333200
72511135055531443
oct275131430350040
951023240445280
1013000000000032
1141622a60aa821
12155b5a1844200
13733b82988436
1432d2bc02565a
1517825e686cdc
hexbd2cc61d020

13000000000032 has 108 divisors (see below), whose sum is σ = 37215216322830. Its totient is φ = 4304633587200.

The previous prime is 13000000000027. The next prime is 13000000000033. The reversal of 13000000000032 is 23000000000031.

It is a happy number.

It can be written as a sum of positive squares in only one way, i.e., 8373870087696 + 4626129912336 = 2893764^2 + 2150844^2 .

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 12999999999933 and 13000000000023.

It is not an unprimeable number, because it can be changed into a prime (13000000000033) by changing a digit.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 5576844 + ... + 7556532.

Almost surely, 213000000000032 is an apocalyptic number.

13000000000032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13000000000032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18607608161415).

13000000000032 is an abundant number, since it is smaller than the sum of its proper divisors (24215216322798).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000000000032 is a wasteful number, since it uses less digits than its factorization.

13000000000032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1980007 (or 1979845 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 9.

Adding to 13000000000032 its reverse (23000000000031), we get a palindrome (36000000000063).

Subtracting 13000000000032 from its reverse (23000000000031), we obtain a palindrome (9999999999999).

The spelling of 13000000000032 in words is "thirteen trillion, thirty-two", and thus it is an aban number and an uban number.

Divisors: 1 2 3 4 6 8 9 12 16 18 24 32 36 48 72 96 144 151 288 302 453 604 906 1208 1359 1812 2416 2718 3624 4832 5436 7248 10872 14496 21744 22801 43488 45602 68403 91204 136806 182408 205209 273612 364816 410418 547224 729632 820836 1094448 1641672 1979689 2188896 3283344 3959378 5939067 6566688 7918756 11878134 15837512 17817201 23756268 31675024 35634402 47512536 63350048 71268804 95025072 142537608 190050144 285075216 298933039 570150432 597866078 896799117 1195732156 1793598234 2391464312 2690397351 3587196468 4782928624 5380794702 7174392936 9565857248 10761589404 14348785872 21523178808 28697571744 43046357616 45138888889 86092715232 90277777778 135416666667 180555555556 270833333334 361111111112 406250000001 541666666668 722222222224 812500000002 1083333333336 1444444444448 1625000000004 2166666666672 3250000000008 4333333333344 6500000000016 13000000000032