Base | Representation |
---|---|
bin | 1011110100101100110001… |
… | …1000011101000000100000 |
3 | 1201000210021100111112022200 |
4 | 2331023030120131000200 |
5 | 3200443000000000112 |
6 | 43352041220333200 |
7 | 2511135055531443 |
oct | 275131430350040 |
9 | 51023240445280 |
10 | 13000000000032 |
11 | 41622a60aa821 |
12 | 155b5a1844200 |
13 | 733b82988436 |
14 | 32d2bc02565a |
15 | 17825e686cdc |
hex | bd2cc61d020 |
13000000000032 has 108 divisors (see below), whose sum is σ = 37215216322830. Its totient is φ = 4304633587200.
The previous prime is 13000000000027. The next prime is 13000000000033. The reversal of 13000000000032 is 23000000000031.
It is a happy number.
It can be written as a sum of positive squares in only one way, i.e., 8373870087696 + 4626129912336 = 2893764^2 + 2150844^2 .
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 12999999999933 and 13000000000023.
It is not an unprimeable number, because it can be changed into a prime (13000000000033) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 5576844 + ... + 7556532.
Almost surely, 213000000000032 is an apocalyptic number.
13000000000032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13000000000032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18607608161415).
13000000000032 is an abundant number, since it is smaller than the sum of its proper divisors (24215216322798).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13000000000032 is a wasteful number, since it uses less digits than its factorization.
13000000000032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1980007 (or 1979845 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 9.
Adding to 13000000000032 its reverse (23000000000031), we get a palindrome (36000000000063).
Subtracting 13000000000032 from its reverse (23000000000031), we obtain a palindrome (9999999999999).
The spelling of 13000000000032 in words is "thirteen trillion, thirty-two", and thus it is an aban number and an uban number.
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