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130002456468431 is a prime number
BaseRepresentation
bin11101100011110010001110…
…001111001101101111001111
3122001022010001201021210222002
4131203302032033031233033
5114014430012323442211
61140254145400342515
736245240030303141
oct3543621617155717
9561263051253862
10130002456468431
1138471806579328
12126b741b774a3b
1357702434824c1
14241621c51ac91
1510069e007603b
hex763c8e3cdbcf

130002456468431 has 2 divisors, whose sum is σ = 130002456468432. Its totient is φ = 130002456468430.

The previous prime is 130002456468359. The next prime is 130002456468433. The reversal of 130002456468431 is 134864654200031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130002456468431 - 246 = 59633712290767 is a prime.

It is a super-2 number, since 2×1300024564684312 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 130002456468433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130002456468433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65001228234215 + 65001228234216.

It is an arithmetic number, because the mean of its divisors is an integer number (65001228234216).

Almost surely, 2130002456468431 is an apocalyptic number.

130002456468431 is a deficient number, since it is larger than the sum of its proper divisors (1).

130002456468431 is an equidigital number, since it uses as much as digits as its factorization.

130002456468431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1658880, while the sum is 47.

The spelling of 130002456468431 in words is "one hundred thirty trillion, two billion, four hundred fifty-six million, four hundred sixty-eight thousand, four hundred thirty-one".