Base | Representation |
---|---|
bin | 11101100011110010110101… |
… | …111010001000101010000000 |
3 | 122001022011210002122220111012 |
4 | 131203302311322020222000 |
5 | 114014432343214444412 |
6 | 1140254335413540052 |
7 | 36245262361425362 |
oct | 3543626572105200 |
9 | 561264702586435 |
10 | 130003122031232 |
11 | 3847201823752a |
12 | 126b7586644628 |
13 | 577031b325048 |
14 | 2416282a8cd32 |
15 | 1006a2d6e4c22 |
hex | 763cb5e88a80 |
130003122031232 has 64 divisors (see below), whose sum is σ = 268732509881640. Its totient is φ = 62592753991680.
The previous prime is 130003122031199. The next prime is 130003122031241. The reversal of 130003122031232 is 232130221300031.
It can be written as a sum of positive squares in 4 ways, for example, as 98021563541056 + 31981558490176 = 9900584^2 + 5655224^2 .
It is a tau number, because it is divible by the number of its divisors (64).
It is a junction number, because it is equal to n+sod(n) for n = 130003122031198 and 130003122031207.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 141035369 + ... + 141954152.
Almost surely, 2130003122031232 is an apocalyptic number.
It is an amenable number.
130003122031232 is an abundant number, since it is smaller than the sum of its proper divisors (138729387850408).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130003122031232 is an equidigital number, since it uses as much as digits as its factorization.
130003122031232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 282989669 (or 282989657 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 130003122031232 its reverse (232130221300031), we get a palindrome (362133343331263).
The spelling of 130003122031232 in words is "one hundred thirty trillion, three billion, one hundred twenty-two million, thirty-one thousand, two hundred thirty-two".
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