Base | Representation |
---|---|
bin | 111100100010011001… |
… | …0110110101000100110 |
3 | 110102120010221211221201 |
4 | 1321010302312220212 |
5 | 4112221304404200 |
6 | 135420031433114 |
7 | 12251412654256 |
oct | 1710462665046 |
9 | 412503854851 |
10 | 130003200550 |
11 | 50152465813 |
12 | 2124198579a |
13 | c34a755552 |
14 | 6413a9d966 |
15 | 35ad296c6a |
hex | 1e44cb6a26 |
130003200550 has 24 divisors (see below), whose sum is σ = 241862238576. Its totient is φ = 51989175840.
The previous prime is 130003200533. The next prime is 130003200563. The reversal of 130003200550 is 55002300031.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 84097 + ... + 516796.
It is an arithmetic number, because the mean of its divisors is an integer number (10077593274).
Almost surely, 2130003200550 is an apocalyptic number.
130003200550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130003200550 is a deficient number, since it is larger than the sum of its proper divisors (111859038026).
130003200550 is a wasteful number, since it uses less digits than its factorization.
130003200550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 605232 (or 605227 counting only the distinct ones).
The product of its (nonzero) digits is 450, while the sum is 19.
Adding to 130003200550 its reverse (55002300031), we get a palindrome (185005500581).
The spelling of 130003200550 in words is "one hundred thirty billion, three million, two hundred thousand, five hundred fifty".
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