Base | Representation |
---|---|
bin | 111100100010011001… |
… | …1001110111100001111 |
3 | 110102120011010220112011 |
4 | 1321010303032330033 |
5 | 4112221321100421 |
6 | 135420033522051 |
7 | 12251413550446 |
oct | 1710463167417 |
9 | 412504126464 |
10 | 130003300111 |
11 | 501525235a3 |
12 | 21241a13327 |
13 | c34a78b969 |
14 | 6413ac7d5d |
15 | 35ad2b64e1 |
hex | 1e44ccef0f |
130003300111 has 2 divisors, whose sum is σ = 130003300112. Its totient is φ = 130003300110.
The previous prime is 130003300109. The next prime is 130003300139. The reversal of 130003300111 is 111003300031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130003300111 - 21 = 130003300109 is a prime.
It is a super-2 number, since 2×1300033001112 (a number of 23 digits) contains 22 as substring.
Together with 130003300109, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 130003300091 and 130003300100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130003300211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65001650055 + 65001650056.
It is an arithmetic number, because the mean of its divisors is an integer number (65001650056).
Almost surely, 2130003300111 is an apocalyptic number.
130003300111 is a deficient number, since it is larger than the sum of its proper divisors (1).
130003300111 is an equidigital number, since it uses as much as digits as its factorization.
130003300111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27, while the sum is 13.
Adding to 130003300111 its reverse (111003300031), we get a palindrome (241006600142).
The spelling of 130003300111 in words is "one hundred thirty billion, three million, three hundred thousand, one hundred eleven".
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