130011202231230 has 32 divisors (see below), whose sum is σ = 315532805421600. Its totient is φ = 34280107254272.

The previous prime is 130011202231201. The next prime is 130011202231291. The reversal of 130011202231230 is 32132202110031.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130011202231197 and 130011202231206.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24346664415 + ... + 24346669754.

It is an arithmetic number, because the mean of its divisors is an integer number (9860400169425).

Almost surely, 2^{130011202231230} is an apocalyptic number.

130011202231230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130011202231230 is an abundant number, since it is smaller than the sum of its proper divisors (185521603190370).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130011202231230 is a wasteful number, since it uses less digits than its factorization.

130011202231230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48693334268.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 130011202231230 its reverse (32132202110031), we get a palindrome (162143404341261).

The spelling of 130011202231230 in words is "one hundred thirty trillion, eleven billion, two hundred two million, two hundred thirty-one thousand, two hundred thirty".