Base | Representation |
---|---|
bin | 1011110100110000111111… |
… | …0111110101101100110110 |
3 | 1201000220012021010101101122 |
4 | 2331030033313311230312 |
5 | 3201002304332113420 |
6 | 43352345425423542 |
7 | 2511205115115662 |
oct | 275141767655466 |
9 | 51026167111348 |
10 | 13001132301110 |
11 | 4162827277338 |
12 | 155b858a9abb2 |
13 | 734003438585 |
14 | 32d3885718a2 |
15 | 1782c8c9d725 |
hex | bd30fdf5b36 |
13001132301110 has 16 divisors (see below), whose sum is σ = 23446783922256. Its totient is φ = 5190509413728.
The previous prime is 13001132301043. The next prime is 13001132301149. The reversal of 13001132301110 is 1110323110031.
It is a super-2 number, since 2×130011323011102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1242932849 + ... + 1242943308.
It is an arithmetic number, because the mean of its divisors is an integer number (1465423995141).
Almost surely, 213001132301110 is an apocalyptic number.
13001132301110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13001132301110 is a deficient number, since it is larger than the sum of its proper divisors (10445651621146).
13001132301110 is a wasteful number, since it uses less digits than its factorization.
13001132301110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2485876687.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13001132301110 its reverse (1110323110031), we get a palindrome (14111455411141).
The spelling of 13001132301110 in words is "thirteen trillion, one billion, one hundred thirty-two million, three hundred one thousand, one hundred ten".
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