Base | Representation |
---|---|
bin | 111100100010101001… |
… | …0010000010111111000 |
3 | 110102120201110001222112 |
4 | 1321011102100113320 |
5 | 4112230411314230 |
6 | 135420524111452 |
7 | 12251542641041 |
oct | 1710522202770 |
9 | 412521401875 |
10 | 130011432440 |
11 | 5015707852a |
12 | 21244695588 |
13 | c34c3783a6 |
14 | 6414c038c8 |
15 | 35add70d95 |
hex | 1e454905f8 |
130011432440 has 32 divisors (see below), whose sum is σ = 309733120080. Its totient is φ = 48945480192.
The previous prime is 130011432409. The next prime is 130011432479. The reversal of 130011432440 is 44234110031.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 95595962 + ... + 95597321.
Almost surely, 2130011432440 is an apocalyptic number.
130011432440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130011432440 is an abundant number, since it is smaller than the sum of its proper divisors (179721687640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130011432440 is a wasteful number, since it uses less digits than its factorization.
130011432440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 191193311 (or 191193307 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 130011432440 its reverse (44234110031), we get a palindrome (174245542471).
It can be divided in two parts, 13001 and 1432440, that added together give a palindrome (1445441).
The spelling of 130011432440 in words is "one hundred thirty billion, eleven million, four hundred thirty-two thousand, four hundred forty".
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