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130013011320 = 233515146315497
BaseRepresentation
bin111100100010101100…
…0010001110101111000
3110102120211102021210120
41321011120101311320
54112231312330240
6135421022013240
712251562235143
oct1710530216570
9412524367716
10130013011320
1150157a56795
1221245117220
13c34c7abc3a
1464150d505a
1535ae083ad0
hex1e45611d78

130013011320 has 128 divisors (see below), whose sum is σ = 393495459840. Its totient is φ = 34363929600.

The previous prime is 130013011319. The next prime is 130013011321. The reversal of 130013011320 is 23110310031.

It is an interprime number because it is at equal distance from previous prime (130013011319) and next prime (130013011321).

It is a super-2 number, since 2×1300130113202 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 130013011320.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130013011321) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8381812 + ... + 8397308.

It is an arithmetic number, because the mean of its divisors is an integer number (3074183280).

Almost surely, 2130013011320 is an apocalyptic number.

130013011320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130013011320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (196747729920).

130013011320 is an abundant number, since it is smaller than the sum of its proper divisors (263482448520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130013011320 is a wasteful number, since it uses less digits than its factorization.

130013011320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16125 (or 16121 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 130013011320 its reverse (23110310031), we get a palindrome (153123321351).

The spelling of 130013011320 in words is "one hundred thirty billion, thirteen million, eleven thousand, three hundred twenty".

Divisors: 1 2 3 4 5 6 8 10 12 15 20 24 30 40 60 120 151 302 453 463 604 755 906 926 1208 1389 1510 1812 1852 2265 2315 2778 3020 3624 3704 4530 4630 5556 6040 6945 9060 9260 11112 13890 15497 18120 18520 27780 30994 46491 55560 61988 69913 77485 92982 123976 139826 154970 185964 209739 232455 279652 309940 349565 371928 419478 464910 559304 619880 699130 838956 929820 1048695 1398260 1677912 1859640 2097390 2340047 2796520 4194780 4680094 7020141 7175111 8389560 9360188 11700235 14040282 14350222 18720376 21525333 23400470 28080564 28700444 35100705 35875555 43050666 46800940 56161128 57400888 70201410 71751110 86101332 93601880 107626665 140402820 143502220 172202664 215253330 280805640 287004440 430506660 861013320 1083441761 2166883522 3250325283 4333767044 5417208805 6500650566 8667534088 10834417610 13001301132 16251626415 21668835220 26002602264 32503252830 43337670440 65006505660 130013011320