Base | Representation |
---|---|
bin | 10010111010110110000… |
… | …010000111110110000010 |
3 | 11121021212120202010021120 |
4 | 102322312002013312002 |
5 | 132300133314224442 |
6 | 2433135014333110 |
7 | 162634351535136 |
oct | 22726602076602 |
9 | 4537776663246 |
10 | 1300134133122 |
11 | 461424907410 |
12 | 18bb8435a196 |
13 | 957a9b2c256 |
14 | 46cd93033c6 |
15 | 23c45abd4ec |
hex | 12eb6087d82 |
1300134133122 has 64 divisors (see below), whose sum is σ = 2858808314880. Its totient is φ = 390909528000.
The previous prime is 1300134133099. The next prime is 1300134133139. The reversal of 1300134133122 is 2213314310031.
It is a junction number, because it is equal to n+sod(n) for n = 1300134133092 and 1300134133101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8424529 + ... + 8577467.
It is an arithmetic number, because the mean of its divisors is an integer number (44668879920).
Almost surely, 21300134133122 is an apocalyptic number.
1300134133122 is an abundant number, since it is smaller than the sum of its proper divisors (1558674181758).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300134133122 is a wasteful number, since it uses less digits than its factorization.
1300134133122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 153959.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1300134133122 its reverse (2213314310031), we get a palindrome (3513448443153).
The spelling of 1300134133122 in words is "one trillion, three hundred billion, one hundred thirty-four million, one hundred thirty-three thousand, one hundred twenty-two".
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