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13001344000 = 21053101573
BaseRepresentation
bin11000001101111000…
…01100010000000000
31020120002022201002021
430012330030100000
5203111321002000
65550035531224
7640120413001
oct140674142000
936502281067
1013001344000
115571a131a7
12262a159b14
1312c2752678
148b49d91a8
1551161a11a
hex306f0c400

13001344000 has 88 divisors (see below), whose sum is σ = 32435828568. Its totient is φ = 5200486400.

The previous prime is 13001343989. The next prime is 13001344009. The reversal of 13001344000 is 44310031.

It can be written as a sum of positive squares in 4 ways, for example, as 428655616 + 12572688384 = 20704^2 + 112128^2 .

It is a Harshad number since it is a multiple of its sum of digits (16).

It is not an unprimeable number, because it can be changed into a prime (13001344009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 77214 + ... + 178786.

It is an arithmetic number, because the mean of its divisors is an integer number (368588961).

Almost surely, 213001344000 is an apocalyptic number.

13001344000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13001344000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16217914284).

13001344000 is an abundant number, since it is smaller than the sum of its proper divisors (19434484568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001344000 is an equidigital number, since it uses as much as digits as its factorization.

13001344000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101608 (or 101580 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 13001344000 its reverse (44310031), we get a palindrome (13045654031).

The spelling of 13001344000 in words is "thirteen billion, one million, three hundred forty-four thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 40 50 64 80 100 125 128 160 200 250 256 320 400 500 512 640 800 1000 1024 1280 1600 2000 2560 3200 4000 5120 6400 8000 12800 16000 25600 32000 64000 101573 128000 203146 406292 507865 812584 1015730 1625168 2031460 2539325 3250336 4062920 5078650 6500672 8125840 10157300 12696625 13001344 16251680 20314600 25393250 26002688 32503360 40629200 50786500 52005376 65006720 81258400 101573000 104010752 130013440 162516800 203146000 260026880 325033600 406292000 520053760 650067200 812584000 1300134400 1625168000 2600268800 3250336000 6500672000 13001344000