13001411120 has 40 divisors (see below), whose sum is σ = 30236536464. Its totient is φ = 5199144192.

The previous prime is 13001411077. The next prime is 13001411131. The reversal of 13001411120 is 2111410031.

It is a tau number, because it is divible by the number of its divisors (40).

It is a super-2 number, since 2×13001411120² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13001411095 and 13001411104.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 301982 + ... + 342338.

Almost surely, 2^13001411120 is an apocalyptic number.

13001411120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13001411120 is an abundant number, since it is smaller than the sum of its proper divisors (17235125344).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001411120 is a wasteful number, since it uses less digits than its factorization.

13001411120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44397 (or 44391 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 13001411120 its reverse (2111410031), we get a palindrome (15112821151).

The spelling of 13001411120 in words is "thirteen billion, one million, four hundred eleven thousand, one hundred twenty".