Base | Representation |
---|---|
bin | 111100100010101110… |
… | …0011110100000011001 |
3 | 110102120220111012022221 |
4 | 1321011130132200121 |
5 | 4112232103034034 |
6 | 135421101344041 |
7 | 12251604500353 |
oct | 1710534364031 |
9 | 412526435287 |
10 | 130014111769 |
11 | 50158638553 |
12 | 21245568021 |
13 | c34caa5aa9 |
14 | 64153000d3 |
15 | 35ae1eebb4 |
hex | 1e4571e819 |
130014111769 has 2 divisors, whose sum is σ = 130014111770. Its totient is φ = 130014111768.
The previous prime is 130014111751. The next prime is 130014111811. The reversal of 130014111769 is 967111410031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92803701769 + 37210410000 = 304637^2 + 192900^2 .
It is a cyclic number.
It is not a de Polignac number, because 130014111769 - 25 = 130014111737 is a prime.
It is a super-2 number, since 2×1300141117692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130014111739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007055884 + 65007055885.
It is an arithmetic number, because the mean of its divisors is an integer number (65007055885).
Almost surely, 2130014111769 is an apocalyptic number.
It is an amenable number.
130014111769 is a deficient number, since it is larger than the sum of its proper divisors (1).
130014111769 is an equidigital number, since it uses as much as digits as its factorization.
130014111769 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 34.
The spelling of 130014111769 in words is "one hundred thirty billion, fourteen million, one hundred eleven thousand, seven hundred sixty-nine".
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