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130021434043309 is a prime number
BaseRepresentation
bin11101100100000011111001…
…011000111010101110101101
3122001100221001021221111121201
4131210003321120322232231
5114020232344103341214
61140311004443525501
736246511226106604
oct3544037130725655
9561327037844551
10130021434043309
1138479864958206
12126bb037229891
135771c7909aa53
1424170dcad8a3b
151007251181274
hex7640f963abad

130021434043309 has 2 divisors, whose sum is σ = 130021434043310. Its totient is φ = 130021434043308.

The previous prime is 130021434043307. The next prime is 130021434043327. The reversal of 130021434043309 is 903340434120031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127309473922500 + 2711960120809 = 11283150^2 + 1646803^2 .

It is a cyclic number.

It is not a de Polignac number, because 130021434043309 - 21 = 130021434043307 is a prime.

Together with 130021434043307, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130021434043307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65010717021654 + 65010717021655.

It is an arithmetic number, because the mean of its divisors is an integer number (65010717021655).

Almost surely, 2130021434043309 is an apocalyptic number.

It is an amenable number.

130021434043309 is a deficient number, since it is larger than the sum of its proper divisors (1).

130021434043309 is an equidigital number, since it uses as much as digits as its factorization.

130021434043309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 37.

The spelling of 130021434043309 in words is "one hundred thirty trillion, twenty-one billion, four hundred thirty-four million, forty-three thousand, three hundred nine".