Base | Representation |
---|---|
bin | 11101100100000011111001… |
… | …011000111010101110101110 |
3 | 122001100221001021221111121202 |
4 | 131210003321120322232232 |
5 | 114020232344103341220 |
6 | 1140311004443525502 |
7 | 36246511226106605 |
oct | 3544037130725656 |
9 | 561327037844552 |
10 | 130021434043310 |
11 | 38479864958207 |
12 | 126bb037229892 |
13 | 5771c7909aa54 |
14 | 24170dcad8a3c |
15 | 1007251181275 |
hex | 7640f963abae |
130021434043310 has 64 divisors (see below), whose sum is σ = 244818723041280. Its totient is φ = 49624333735680.
The previous prime is 130021434043309. The next prime is 130021434043327. The reversal of 130021434043310 is 13340434120031.
It is a happy number.
It is a super-2 number, since 2×1300214340433102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 150620501 + ... + 151481279.
It is an arithmetic number, because the mean of its divisors is an integer number (3825292547520).
Almost surely, 2130021434043310 is an apocalyptic number.
130021434043310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130021434043310 is a deficient number, since it is larger than the sum of its proper divisors (114797288997970).
130021434043310 is a wasteful number, since it uses less digits than its factorization.
130021434043310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 862433.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 130021434043310 its reverse (13340434120031), we get a palindrome (143361868163341).
The spelling of 130021434043310 in words is "one hundred thirty trillion, twenty-one billion, four hundred thirty-four million, forty-three thousand, three hundred ten".
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