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130022414124 = 22310835201177
BaseRepresentation
bin111100100010111110…
…0001001011100101100
3110102121111010000000120
41321011330021130230
54112241214222444
6135421555324540
712252035166441
oct1710574113454
9412544100016
10130022414124
11501622991a9
12212482b0750
13c351721a25
1464164619c8
1535aecdeb19
hex1e45f0972c

130022414124 has 12 divisors (see below), whose sum is σ = 303385632984. Its totient is φ = 43340804704.

The previous prime is 130022414057. The next prime is 130022414177. The reversal of 130022414124 is 421414220031.

It is a tau number, because it is divible by the number of its divisors (12).

It is a junction number, because it is equal to n+sod(n) for n = 130022414094 and 130022414103.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5417600577 + ... + 5417600600.

It is an arithmetic number, because the mean of its divisors is an integer number (25282136082).

Almost surely, 2130022414124 is an apocalyptic number.

It is an amenable number.

130022414124 is an abundant number, since it is smaller than the sum of its proper divisors (173363218860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130022414124 is a wasteful number, since it uses less digits than its factorization.

130022414124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10835201184 (or 10835201182 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 130022414124 its reverse (421414220031), we get a palindrome (551436634155).

The spelling of 130022414124 in words is "one hundred thirty billion, twenty-two million, four hundred fourteen thousand, one hundred twenty-four".

Divisors: 1 2 3 4 6 12 10835201177 21670402354 32505603531 43340804708 65011207062 130022414124