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13002311011200 = 273527461419711
BaseRepresentation
bin1011110100110101011000…
…1000010000101110000000
31201001000020102002001122220
42331031112020100232000
53201012213104324300
643353102413331040
72511246250023360
oct275152610205600
951030212061586
1013002311011200
114163281661705
12155bb27796a80
137341606b7474
1432d45ad1c9a0
151783474d0da0
hexbd356210b80

13002311011200 has 384 divisors, whose sum is σ = 49050700554240. Its totient is φ = 2965502976000.

The previous prime is 13002311011199. The next prime is 13002311011223. The reversal of 13002311011200 is 211011320031.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13002311011200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 30769345 + ... + 31189055.

It is an arithmetic number, because the mean of its divisors is an integer number (127736199360).

Almost surely, 213002311011200 is an apocalyptic number.

13002311011200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13002311011200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24525350277120).

13002311011200 is an abundant number, since it is smaller than the sum of its proper divisors (36048389543040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13002311011200 is a wasteful number, since it uses less digits than its factorization.

13002311011200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 420206 (or 420189 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13002311011200 its reverse (211011320031), we get a palindrome (13213322331231).

The spelling of 13002311011200 in words is "thirteen trillion, two billion, three hundred eleven million, eleven thousand, two hundred".