Base | Representation |
---|---|
bin | 10010111010111101001… |
… | …001010000110101000000 |
3 | 11121022011220020211000022 |
4 | 102322331021100311000 |
5 | 132300404340223230 |
6 | 2433154515513012 |
7 | 162640330633355 |
oct | 22727511206500 |
9 | 4538156224008 |
10 | 1300253445440 |
11 | 461486199534 |
12 | 18bbb82b8768 |
13 | 957c8775161 |
14 | 46d0b0c062c |
15 | 23c512da1e5 |
hex | 12ebd250d40 |
1300253445440 has 28 divisors (see below), whose sum is σ = 3096228517716. Its totient is φ = 520101378048.
The previous prime is 1300253445367. The next prime is 1300253445451. The reversal of 1300253445440 is 445443520031.
It can be written as a sum of positive squares in 2 ways, for example, as 939782891776 + 360470553664 = 969424^2 + 600392^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 1300253445440.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2031645689 + ... + 2031646328.
Almost surely, 21300253445440 is an apocalyptic number.
1300253445440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1300253445440 is an abundant number, since it is smaller than the sum of its proper divisors (1795975072276).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300253445440 is an equidigital number, since it uses as much as digits as its factorization.
1300253445440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4063292034 (or 4063292024 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 35.
Adding to 1300253445440 its reverse (445443520031), we get a palindrome (1745696965471).
The spelling of 1300253445440 in words is "one trillion, three hundred billion, two hundred fifty-three million, four hundred forty-five thousand, four hundred forty".
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