Base | Representation |
---|---|
bin | 11101100100001101101111… |
… | …010100000110001001010111 |
3 | 122001101221022211012221102210 |
4 | 131210031233110012021113 |
5 | 114020421020110103211 |
6 | 1140315513253004503 |
7 | 36250334144633361 |
oct | 3544155724061127 |
9 | 561357284187383 |
10 | 130032002425431 |
11 | 38483298495107 |
12 | 127010a6623733 |
13 | 5772c717635b2 |
14 | 2417822533d31 |
15 | 100766ddb39a6 |
hex | 76436f506257 |
130032002425431 has 64 divisors (see below), whose sum is σ = 193304755998720. Its totient is φ = 77373574686720.
The previous prime is 130032002425427. The next prime is 130032002425459. The reversal of 130032002425431 is 134524200230031.
It is not a de Polignac number, because 130032002425431 - 22 = 130032002425427 is a prime.
It is a super-2 number, since 2×1300320024254312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130032002425421) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 68528436 + ... + 70400358.
It is an arithmetic number, because the mean of its divisors is an integer number (3020386812480).
Almost surely, 2130032002425431 is an apocalyptic number.
130032002425431 is a deficient number, since it is larger than the sum of its proper divisors (63272753573289).
130032002425431 is a wasteful number, since it uses less digits than its factorization.
130032002425431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1872856.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 130032002425431 its reverse (134524200230031), we get a palindrome (264556202655462).
The spelling of 130032002425431 in words is "one hundred thirty trillion, thirty-two billion, two million, four hundred twenty-five thousand, four hundred thirty-one".
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