Base | Representation |
---|---|
bin | 11101100100001101110110… |
… | …011001100111001101101110 |
3 | 122001101221122002221000022010 |
4 | 131210031312121213031232 |
5 | 114020421241023441420 |
6 | 1140315533141102050 |
7 | 36250340120306643 |
oct | 3544156631471556 |
9 | 561357562830263 |
10 | 130032121312110 |
11 | 38483349606466 |
12 | 1270111a3b7926 |
13 | 5772c9028a844 |
14 | 241783423ddca |
15 | 10076795494e0 |
hex | 76437666736e |
130032121312110 has 64 divisors (see below), whose sum is σ = 312148370309184. Its totient is φ = 34667313408000.
The previous prime is 130032121312099. The next prime is 130032121312123. The reversal of 130032121312110 is 11213121230031.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3578092540 + ... + 3578128880.
It is an arithmetic number, because the mean of its divisors is an integer number (4877318286081).
Almost surely, 2130032121312110 is an apocalyptic number.
130032121312110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130032121312110 is an abundant number, since it is smaller than the sum of its proper divisors (182116248997074).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130032121312110 is a wasteful number, since it uses less digits than its factorization.
130032121312110 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60309.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 130032121312110 its reverse (11213121230031), we get a palindrome (141245242542141).
The spelling of 130032121312110 in words is "one hundred thirty trillion, thirty-two billion, one hundred twenty-one million, three hundred twelve thousand, one hundred ten".
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