130032310000 has 50 divisors (see below), whose sum is σ = 314821249952. Its totient is φ = 52012920000.

The previous prime is 130032309997. The next prime is 130032310087. The reversal of 130032310000 is 13230031.

It is a tau number, because it is divible by the number of its divisors (50).

It is a super-2 number, since 2×130032310000² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 6491616 + ... + 6511615.

Almost surely, 2^130032310000 is an apocalyptic number.

130032310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130032310000 is an abundant number, since it is smaller than the sum of its proper divisors (184788939952).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130032310000 is an equidigital number, since it uses as much as digits as its factorization.

130032310000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13003259 (or 13003238 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 130032310000 its reverse (13230031), we get a palindrome (130045540031).

The spelling of 130032310000 in words is "one hundred thirty billion, thirty-two million, three hundred ten thousand".